रु 4000रु 2500रु 3000रु 3050
Answer : c
Solution : (c) Amount `(A_(1))` = Rs. 4500, <br> `t_(1) = 2 "years"` <br> Amount `(A_(2))` = Rs. 6750, <br> `t_(2) ` = 2 years <br> Let Rate % = R% , <br> Principal = Rs. P According to the question , <br> Case (I) : 4500 = `P(1 + (R)/(100))^(2)………..(i)` <br> Case (II) : 6750 <br> `= P(1+(R)/(100))^(4)............(i)` <br> By dividing equation (ii), by equation (i) (समीकारण (ii ) को समीकारण (i ) से भाग करने पर ) `= (6750)/(4500) = (1+(R)/(100))^(2)` <br> `(3)/(2) = (1 +(R)/(100))^(2)........(ii)` <br> From equation (i) `4500 = P xx(3)/(2)` <br> P = Rs. 3000 <br> Hence Required principal <br> Alternate <br> Note : In such type of question to save your valuable time follow the given below method . <br> ( नोट : इस प्रकार के प्रशनो मे अपनी बहुमूल्य समय के बचत के लिए आप नीचे दी गयी विधा का प्रयोग कर सकते है |) <br> Let principal = Rs. P <br> According to the question <br> <img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/RKY_MATH_C18_E01_015_S01.png" width="80%"> <br> `Pxx(3)/(2) = 4500, P = (4500xx 2)/(3)` <br> =Rs. 3000 <br> Hence required principal <br> Rs. 3000